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What is work done on dipole to rotate it...

What is work done on dipole to rotate it form stable equilibrium position `(theta_(1) = 0^(@))` to unstable equilibrium `(theta_(2) = 180^(@))` ?

Text Solution

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`w = MB (cos theta _(1) - cos theta _(2)) = MB [cos 0^(@) - cos 180^(@)] = MB [1- (-1)]`
`w = 2MB.`
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