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A short bar magnet is kept in uniform ma...

A short bar magnet is kept in uniform magnetic field of `0.16` T such that dipole moment vector is at angle `30^(@)` with the field . The torque acting on the bar magnet is 0.032 N m . What is the magnitude of magnetic dipole moment of the magnet ?

Text Solution

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`tau = MB sin theta`
` implies 0.032 = M xx 0.16 xx 1/2`
`implies 0.064 = M xx 0.16`
`implies M = (6.4)/(16) = 0.4Am^(2)`
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