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A bar magnet of magnetic dipole moment 1...

A bar magnet of magnetic dipole moment `10 Am^(2)` is in stable equilibrium . If it is rotated through `30^(@)` , find its potential energy in new position [Given , B = 0.2 T]

Text Solution

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`M = 10 Åm ^(2)`
`B = 0.2T`
`U =-MB cos theta`
`=- 10 xx 0.2 xx (sqrt3)/(2)`
`=- sqrt3 J`
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