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A magnetising field of 1600 Am^(-1) prod...

A magnetising field of `1600 Am^(-1)` produces a magnetic flux `2.4 xx 10^(-5)` weber in an iron bar of cross-sectional area `0.2 cm^(2)` . The susceptibility of the iron bar will be

A. 1788
B. 1192
C. 596
D. 298

A

1788

B

1192

C

596

D

298

Text Solution

Verified by Experts

The correct Answer is:
C

`mu = B/H = (phi)/(AH)`
` = (2.4 xx 10 ^(-5))/(0.2 xx 10 ^(-4) xx 16 xx 10 ^(2))`
`= (2.4 xx 10 ^(-5))/(16 xx 2 xx 10 ^(-3))`
` = (1.2)/(16) xx 10 ^(-2)`
` = 3/4 xx 10 ^(-3)`
` = 0.75 xx 10 ^(-3) Wb//mA`
`mu _(r) = (0.75 xx 10 ^(-3))/( 4 pi xx 10 ^(-7))`
` mu _(r) = (75)/(4pi) xx 10 ^(2)`
` = 5.9713376`
`mu _(r) = 597`
` x _(m) = mu_(r) -1`
`x _(m) = 597 -1`
` x _(m) = 596`
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