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A thin magnetic needle oscillates in a h...

A thin magnetic needle oscillates in a horizontal plane with a period T. It is broken into n equals parts. The time period of each part will be

A

T/n

B

T

C

T n

D

`1//Tn`

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The correct Answer is:
To solve the problem of determining the time period of each part of a broken magnetic needle, we can follow these steps: ### Step 1: Understand the Initial Conditions The original magnetic needle has a period \( T \). The magnetic moment \( M \) of the needle is defined, and its length is \( L \). The mass of the needle is \( m \). ### Step 2: Write the Formula for Time Period The time period \( T \) of the magnetic needle is given by the formula: \[ T = 2\pi \sqrt{\frac{I}{m \cdot B}} \] where \( I \) is the moment of inertia, \( m \) is the mass, and \( B \) is the magnetic field. ### Step 3: Calculate the Moment of Inertia For a thin rod (the magnetic needle) rotating about its center, the moment of inertia \( I \) is given by: \[ I = \frac{mL^2}{12} \] ### Step 4: Substitute the Moment of Inertia into the Time Period Formula Substituting \( I \) into the time period formula gives: \[ T = 2\pi \sqrt{\frac{\frac{mL^2}{12}}{m \cdot B}} = 2\pi \sqrt{\frac{L^2}{12B}} \] ### Step 5: Break the Needle into \( n \) Equal Parts When the needle is broken into \( n \) equal parts: - Each part will have a length of \( \frac{L}{n} \). - The mass of each part will be \( \frac{m}{n} \). ### Step 6: Calculate the New Moment of Inertia for Each Part The moment of inertia for each part, which is still a thin rod, is: \[ I' = \frac{\frac{m}{n} \left(\frac{L}{n}\right)^2}{12} = \frac{mL^2}{12n^3} \] ### Step 7: Substitute the New Values into the Time Period Formula The new time period \( T' \) for each part will be: \[ T' = 2\pi \sqrt{\frac{I'}{\frac{m}{n} \cdot B}} = 2\pi \sqrt{\frac{\frac{mL^2}{12n^3}}{\frac{m}{n} \cdot B}} = 2\pi \sqrt{\frac{L^2}{12n^2B}} \] ### Step 8: Relate the New Time Period to the Original Time Period From the original time period \( T \): \[ T' = \frac{T}{n} \] ### Conclusion Thus, the time period of each part after breaking the needle into \( n \) equal parts is: \[ T' = \frac{T}{n} \]
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AAKASH INSTITUTE ENGLISH-MAGNETISM AND MATTER -ASSIGNMENT (SECTION A)
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  3. A thin magnetic needle oscillates in a horizontal plane with a period ...

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  8. To shield an instrument from external magnetic field, it is placed ins...

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  9. A dip needle lies initially in the magnetic meridian when it shows...

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  10. If a dip needle is suspended at an angle 30° to the magnetic meridian,...

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  11. A dip needle free to move in a vertical plane perpendiculr to the magn...

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  12. If theta(1) and theta(2) be the apparent angles of dip observed in two...

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