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A charged particle of specific charge (i.e.,Charge per unit mass 0 0.2 C/kg has velocity `2hati-3hatjms^(-1)` at some instant in a uniform magnetic field `5hati+2hatj` (tesla).Find the acceleration of the particle at this instant

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`veca=(vecF)/m=q/m(vecxxvecB)`
`impliesq/m=0.2C//kg`
`vecv=(2hati-3hatj)m//s`
`vecb=(5hati+2hatj)T`
Therefore `veca=0.2(2hati-3hatj)xx(5hati+2hatj)m//s^(2)`
`=0.2[4hatk+15hatk]m//s^(2)`
`veca=3.8hatkm//s^(2)`
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AAKASH INSTITUTE ENGLISH-MOVING CHARGE AND MAGNESIUM-SECTION D
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