What is the net magnetic field at point O for the current distribution shown here?

Explanation

Let `B_(1)=` magnetic field due to circular loop `=(mu_(0)i)/(2r)` inward
and `B_(2)=` magnetic field ue to straight currrent carrying wire `(mu_(0)(4i))/(2pi(2r))=(mu_(0)i)/(pir)` outward
As `B_(1)gtB_(2)`
`implies` Net field `-B_(1)-B_(2)=(mu_(0)i)/(2r)=(mu_(0)i)/(pir)` inward