Write equation for Ampere's circuital law for the Amperian loop shown (traversed in the direction shown by arrow marks put on it)

Explanation

If seen from top, left side portion of the loops is tranversed anticlocwise, while the other portion is traversed clockwise. Thus by sign convention `i_(1)` is positive `i_(2)` is positive `i_(3)` is negative.
Thus `ointvecB.vec(dl)=mu_(0)i=mu_(0)(i_(1)+i_(2)-i_(3))`