Home
Class 12
PHYSICS
A beam of protons is deflected sideways....

A beam of protons is deflected sideways. Could this deflection be caused
(1) By an electric field ?
(2) By a magnetic field ?
(3) If either could be responsible how would you be able to tell which was present ?

Text Solution

Verified by Experts

1. Yes
2.Yes
3.On reversing the direction of the projection of protons, if the protons are deflected in te same direction, then the deflection is due to electric field, if the protons are deflected in the opposite then the deflection is due to magnetic field.
Promotional Banner

Topper's Solved these Questions

  • MOVING CHARGE AND MAGNESIUM

    AAKASH INSTITUTE ENGLISH|Exercise TRY YOURSELF|12 Videos

  • MOVING CHARGE AND MAGNESIUM

    AAKASH INSTITUTE ENGLISH|Exercise EXERCISE|30 Videos

  • MOVING CHARGE AND MAGNESIUM

    AAKASH INSTITUTE ENGLISH|Exercise SECTION D|16 Videos

  • MOTION IN STRAIGHT LINE

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (SECTION - J)|2 Videos

  • MOVING CHARGES AND MAGNETISM

    AAKASH INSTITUTE ENGLISH|Exercise Assignment Section J (Aakash Challengers Questions)|5 Videos

Similar Questions

Explore conceptually related problems

An electron beam projected along positive x-axis deflects along the positive y-axis. If this deflection is caused by a magnetic field, what is the direction of the field?

An electron beam projected along the positive x-axis deflects along the positive y-axis deflects . If this deflection is caused by a magnetic field, what is the direction of the field? Can we conclude that is parallel to the z-axis?

It is observed that: gamma rays are not deflected by either an electric or a magnetic field. Explain observations.

An electron (mass =9.1xx10^(-31)kg , charge =1.6xx10^(-19)C ) experiences no deflection if subjected to an electric field of 3.2x10^(5)V/m , and a magnetic fields of 2.0xx10^(-3)Wb/m^(2) . Both the fields are normal to the path of electron and to each other. If the electric field is removed, then the electron will revolve in an orbit of radius

An electron (mass =9.1xx10^(-31)kg , charge =1.6xx10^(-19)C ) experiences no deflection if subjected to an electric field of 3.2x10^(5)V/m , and a magnetic fields of 2.0xx10^(-3)Wb/m^(2) . Both the fields are normal to the path of electron and to each other. If the electric field is removed, then the electron will revolve in an orbit of radius

A current i, indicated by the crosses in figure, is established in a strip of copper of height h and width w. A uniform field of magnetic induction B is applied at right angle to the strip. (a) Calculate the drift velocity v_d of the electrons. (b) What are the magnitude and direction of the magnetic force F acting on the electrons? (c) What should the magnitude and direction of a homogeneous electric field E be in order to counterbalance the effect of mangetic field? (d) Calculate voltage V necessary between two sides of the conductor in order to creat this field E Between which sides of the conductor would this voltage have to be applied? (e) If no electric field is applied from the outside, the electrons will be pushed somewhat to one side and therefore will give rise to a uniform electric field E_H across the conductor until the forces of this electrostatic field E_H balance the magnetic forces encountered in part (b). What will be the magnitude and direction of field E_H ? Assume that n, the number of conductor electrons per unit volume is 1.1xx10^(29) m^-3, h = 0.02 m, w= 0.1 cm, i = 50 A, and B=2 T.

A beam of cathode rays is subjected to crossed electric (E ) and magnetic fields (B). The fields are adjusted such that the beam is not deflected. The specific charge of the cathode rays is given by

A proton beam is going from north to south and an electron beam is going from south to north. Neglecting the earth's magnetic field, the electron beam will be deflected

Following experiment was performed by J.J. Thomson in order to measure ratio of charge e and mass m of electron. Electrons emitted from a hot filament are accelerated by a potential difference V. As the electrons pass through deflecting plates, they encounter both electric and magnetic fields. the entire region in which electrons leave the plates they enters a field free region that extends to fluorescent screen. The entire region in which electrons travel is evacuated. Firstly, electric and magnetic fields were made zero and position of undeflected electron beam on the screen was noted. The electric field was turned on and resulting deflection was noted. Deflection is given by d_(1) = (eEL^(2))/(2mV^(2)) where L = length of deflecting plate and v = speed of electron. In second part of experiment, magnetic field was adjusted so as to exactly cancel the electric force leaving the electron beam undeflected. This gives eE = evB . Using expression for d_(1) we can find out (e)/(m) = (2d_(1)E)/(B^(2)L^(2)) A beam of electron with velocity 3 xx 10^(7) m s^(-1) is deflected 2 mm while passing through 10 cm in an electric field of 1800 V//m perpendicular to its path. e//m for electron is

Following experiment was performed by J.J. Thomson in order to measure ratio of charge e and mass m of electron. Electrons emitted from a hot filament are accelerated by a potential difference V. As the electrons pass through deflecting plates, they encounter both electric and magnetic fields. the entire region in which electrons leave the plates they enters a field free region that extends to fluorescent screen. The entire region in which electrons travel is evacuated. Firstly, electric and magnetic fields were made zero and position of undeflected electron beam on the screen was noted. The electric field was turned on and resulting deflection was noted. Deflection is given by d_(1) = (eEL^(2))/(2mV^(2)) where L = length of deflecting plate and v = speed of electron. In second part of experiment, magnetic field was adjusted so as to exactly cancel the electric force leaving the electron beam undeflected. This gives eE = evB. Using expression for d_(1) we can find out (e)/(m) = (2d_(1)E)/(B^(2)L^(2)) If the electron is deflected downward when only electric field is turned on, in what direction do the electric and magnetic fields point in second part of experiment