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If a proton enters perpendicularly a mag...

If a proton enters perpendicularly a magnetic field with velocity v, then time period of revolution is T. If proton enters with velocity 2v, then time period will be

A

T

B

2T

C

3T

D

4T

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The correct Answer is:
To solve the problem, we need to analyze the relationship between the time period of revolution of a proton in a magnetic field and its velocity. ### Step-by-Step Solution: 1. **Understanding the Motion of a Charged Particle in a Magnetic Field**: When a charged particle, like a proton, enters a magnetic field perpendicularly, it experiences a magnetic force that causes it to move in a circular path. The magnetic force (Lorentz force) is given by: \[ F = q(\mathbf{v} \times \mathbf{B}) \] where \( q \) is the charge of the proton, \( \mathbf{v} \) is its velocity, and \( \mathbf{B} \) is the magnetic field. 2. **Centripetal Force**: The magnetic force acts as the centripetal force required to keep the proton in circular motion. The centripetal force is given by: \[ F = \frac{mv^2}{R} \] where \( m \) is the mass of the proton, \( v \) is its velocity, and \( R \) is the radius of the circular path. 3. **Equating Forces**: Setting the magnetic force equal to the centripetal force, we have: \[ qvB = \frac{mv^2}{R} \] 4. **Solving for Radius**: Rearranging the equation gives: \[ R = \frac{mv}{qB} \] 5. **Time Period of Revolution**: The time period \( T \) for one complete revolution is given by: \[ T = \frac{2\pi R}{v} \] Substituting the expression for \( R \): \[ T = \frac{2\pi}{v} \cdot \frac{mv}{qB} = \frac{2\pi m}{qB} \] This shows that the time period \( T \) is independent of the velocity \( v \). 6. **Considering the New Velocity**: If the proton enters the magnetic field with a new velocity \( 2v \), we can analyze the time period again: \[ T' = \frac{2\pi m}{qB} \] Since the expression for \( T \) does not include \( v \), the time period remains the same. ### Conclusion: The time period \( T' \) when the proton enters with velocity \( 2v \) is still: \[ T' = T \] Thus, the time period remains unchanged. ### Final Answer: The time period will be \( T \). ---
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AAKASH INSTITUTE ENGLISH-MOVING CHARGE AND MAGNESIUM-ASSIGNMENT (SECTION A)
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