A bullet of mass 10 g moving with a velocity `300 ms^(-1)` strikes a wooden block and comes out from ot her side with a velocity of `200ms^(-1).` Find the work done by t he resistive force on the bullet.

Explanation

To find the work done by the resistive force on the bullet, we can use the work-energy theorem, which states that the work done on an object is equal to the change in its kinetic energy.

### Step-by-Step Solution:

1. **Identify the given values:**
- Mass of the bullet, \( m = 10 \, \text{g} = 10 \times 10^{-3} \, \text{kg} \)
- Initial velocity of the bullet, \( u = 300 \, \text{m/s} \)
- Final velocity of the bullet, \( v = 200 \, \text{m/s} \)
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