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A ball of mass 1 kg is projected with 10...

A ball of mass 1 kg is projected with `10ms^(-1)` from the top of a tower of height 20 m. What is its speed when it is at vertical distance of 10 m below point of projection? `(g=10ms^(-2))`

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To solve the problem step by step, we will use the principles of work and energy. ### Step 1: Identify the given data - Mass of the ball (m) = 1 kg - Initial speed (u) = 10 m/s - Height of the tower (h) = 20 m - Distance below the point of projection (d) = 10 m - Acceleration due to gravity (g) = 10 m/s² ...
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