Home
Class 12
PHYSICS
A body of mass 2 kg moving on a horizont...

A body of mass 2 kg moving on a horizontal surface with a speed `v_(i)=1ms^(-1)` enters a rough patch ranging from `x=0.5m` to `x=1.5m.` If the body comes to rest after passing the patch, then find the retarding force on the body.

Text Solution

AI Generated Solution

To solve the problem step by step, we can follow these steps: ### Step 1: Identify the given values - Mass of the body, \( m = 2 \, \text{kg} \) - Initial speed, \( v_i = 1 \, \text{m/s} \) - Final speed after passing the rough patch, \( v_f = 0 \, \text{m/s} \) - Displacement of the rough patch, \( S = x_2 - x_1 = 1.5 \, \text{m} - 0.5 \, \text{m} = 1 \, \text{m} \) ...
Promotional Banner

Similar Questions

Explore conceptually related problems

A body of mass 2 kg moving on a horiontal surface with speed v_(i)=1ms^(-1) enters a rough patch ranging from x=0.5m to x=1.5m. If the body comes to rest after passing the patch, then find the retarding force on the body.

A block of mass m=1kg moving on a horizontal surface with speed v_(i)=2ms^(-1) enters a rough patch ranging from x0.10m to x=2.01m . The retarding force F_(r) on the block in this range ins inversely proportional to x over this range F_(r)=-(k)/(x) fo r 0.1 lt xlt 2.01m =0 for lt 0.1m and x gt 2.01m where k=0.5J . What is the final K.E. and speed v_(f) of the block as it crosses the patch?

A body of mass 5 kg moving on a horizontal surface with a velocity of 10 ms^(-1) comes to rest in 2s. The force required to make this body move with a velocity of 10 ms^(-1) on the same surface is

A body of mass 2kg moving on a horizontal surface with an initial velocity of 4 ms^(-1) comes to rest after 2 second. If one wants to keep this body moving on the same surface with a velocity of 4 ms^(-1) the force required is

A body is moving along a rough horizontal surface with an initial velocity 6m/s m If the body comes to rest after travelling 9 m , then the coefficient of sliding friction will be

A body of mass 10 kg moves on rough horizontal surface with initial velocity 10m/s and travels 500m before coming to rest. The coefficient of friction is

A body of mass m = 3.513 kg is moving along the x-axis with a speed of 5.00ms^(-1) . The magnetude of its momentum is recorded as

A body of mass m = 3.513 kg is moving along the x-axis with a speed of 5.00ms^(-1) . The magnetude of its momentum is recorded as

A body of mass 2kg is placed on a horizontal surface having kinetic friction 0.4 and static friction 0.5 . If the force applied on the body is 2.5N , then the frictional force acting on the body will be

A body of mass 2 kg is kept on a rough horizontal surface as shown in the figure. If coefficient of friction is 0.5, find the work done by frictional force in the interval t=0 to t=5 sec