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Consider an elastic collision between a ...

Consider an elastic collision between a neutron and a light nuclei like Beryllium and colculate neuton's energy transferred to Beryllium,

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Hint : `f_(1)=(4m_(1)m_(2))/((m_(1)+m_(2))^(2))` using the result of solved example 21
`m_(2)=12m_(1)`
`f_(1)=((m_(1)-m_(2))/(m_(1)+m_(2)))^(2)," Using the result of solved example 21"`
`f=((m_(1)-12m_(1))/(m_(1)+12m_(1)))^(2)," Using m"_(2)=12m_(1)`
`=-((-11)/(13))^(2)=(121)/(169)`
`"Expressed as percent it is "(12100)/(169)=71.6% and f_(2)=28.4%`
In partice, however, this number is smaller as head - on collision are none.
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