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In example 21, consider an elastic colli...

In example 21, consider an elastic collision between a neutron and a light nuclei like carbon and calculate fractional KE lost.

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Hint : `f_(2)=(4m_(1)m_(2))/((m_(1)+m_(2))^(2))` using the result of example 21
Use the fact that `m_(2)=9m_(1)`
`f_(1)=(4m_(1)m_(2))/((m_(1)+m_(2))^(2))," Using the result of example 21"`
`=(4m_(1)(9m_(1)))/((m_(1)+9m_(1)))" as "m_(2)=9m_(1)`
`=(4xx9)/(100)" or "36%`
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