Home
Class 12
PHYSICS
Two bodies having masses m(1) and m(2) a...

Two bodies having masses `m_(1)` and `m_(2)` and velocities `v_(1)` and `v_(2)` colide and form a composite system. If `m_(1)v_(1) + m_(2)v_(2) = 0(m_(1) ne m_(2)`. The velocity of composite system will be

Text Solution

AI Generated Solution

To solve the problem step by step, we will use the principle of conservation of linear momentum. ### Step-by-Step Solution: 1. **Understand the Problem**: We have two bodies with masses \( m_1 \) and \( m_2 \) moving with velocities \( v_1 \) and \( v_2 \) respectively. After colliding, they form a composite system. We need to find the velocity of this composite system. 2. **Apply Conservation of Momentum**: According to the conservation of momentum, the total momentum before the collision must equal the total momentum after the collision. The equation can be written as: \[ ...
Promotional Banner

Similar Questions

Explore conceptually related problems

Two masses, m_(1) and m_(2) , are moving with velocities v_(1) and v_(2) . Find their total kinetic energy in the reference frame of centre of mass.

Two balls A and B of masses m and 2 m are in motion with velocities 2v and v, respectively. Compare: Their momentum.

Two particles of masses m_(1) and m_(2) in projectile motion have velocities vec(v)_(1) and vec(v)_(2) , respectively , at time t = 0 . They collide at time t_(0) . Their velocities become vec(v')_(1) and vec(v')_(2) at time 2 t_(0) while still moving in air. The value of |(m_(1) vec(v')_(1) + m_(2) vec(v')_(2)) - (m_(1) vec(v)_(1) + m_(2) vec(v)_(2))|

Two masses m_(A) and m_(B) moving with velocities v_(A) and v_(B) in opposite direction collide elastically after that the masses m_(A) and m_(B) move with velocity v_(B) and v_(A) respectively. The ratio (m_(A)//m_(B)) is

Two balls A and B of masses m and 2 m are in motion with velocities 2v and v, respectively. Compare: Their inertia.

Use of dilution formula (M_(1)V_(1) = M_(2) V_(2))

Two balls with masses m_(1)=3 and m_(2)=5 kg have initial velocities v_(1)=v_(2)=5m//s in the directions shown in figure. They collide at the origin. a. find the velocioty of the CM 3s before the collision. b. Find the position of the CM 2s after the collision.

Two particles of mass m_(A) and m_(B) and their velocities are V_(A) and V_(B) respectively collides. After collision they interchanges their velocities, then ratio of m_(A)/m_(B) is

Two balls of masses m_(1), m_(2) and speeds v_(1) and v_(2) collide at right angle . The maximum amount of kinetic energy loss due ot inelastic collision is ___.

Two bodies of masses (m_(1)) and (m_(2)) are droppded from heithts h_(1) and h_(2) , respectively. They reach the ground after time t_(1) and t_(2) and strike the ground with v_(1) and v_(2) , respectively Choose the correct relations from the following.