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Under the action of a force, a 2 kg body...

Under the action of a force, a 2 kg body moves such that its position x as a function of time t is given by `x=(t^(3))/(3)`, where x is in metre and t in second. The work done by the force in the first two seconds is

A

1600 J

B

160 J

C

16 J

D

`(16)/(9)J`

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The correct Answer is:
D
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AAKASH INSTITUTE ENGLISH-WORK, ENERGY AND POWER-Assignment (SECTION - A)
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