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Two bodies of masses m(1) and m(2) have...

Two bodies of masses `m_(1) and m_(2)` have same kinetic energy. The ratio of their momentum is

A

`sqrt((m_(2))/(m_(1)))`

B

`sqrt((m_(1))/(m_(2)))`

C

`(m_(1)^(2))/(m_(2)^(2))`

D

`(m_(2)^(2))/(m_(1)^(2))`

Text Solution

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The correct Answer is:
To find the ratio of the momentum of two bodies with the same kinetic energy, we can follow these steps: ### Step 1: Write the formula for kinetic energy The kinetic energy (KE) of an object is given by the formula: \[ KE = \frac{1}{2} m v^2 \] where \( m \) is the mass and \( v \) is the velocity of the object. ### Step 2: Express velocity in terms of momentum Momentum \( p \) is defined as: \[ p = mv \] From this, we can express velocity \( v \) as: \[ v = \frac{p}{m} \] ### Step 3: Substitute velocity into the kinetic energy formula Substituting \( v \) in the kinetic energy formula, we get: \[ KE = \frac{1}{2} m \left(\frac{p}{m}\right)^2 = \frac{1}{2} m \frac{p^2}{m^2} = \frac{p^2}{2m} \] ### Step 4: Set the kinetic energies equal Let the kinetic energies of the two bodies be equal: \[ \frac{p_1^2}{2m_1} = \frac{p_2^2}{2m_2} \] ### Step 5: Simplify the equation Cancel \( \frac{1}{2} \) from both sides: \[ \frac{p_1^2}{m_1} = \frac{p_2^2}{m_2} \] ### Step 6: Rearrange to find the ratio of momentum Rearranging gives: \[ \frac{p_1^2}{p_2^2} = \frac{m_1}{m_2} \] Taking the square root of both sides, we find: \[ \frac{p_1}{p_2} = \sqrt{\frac{m_1}{m_2}} \] ### Conclusion Thus, the ratio of the momentum of the two bodies is: \[ \frac{p_1}{p_2} = \sqrt{\frac{m_1}{m_2}} \]
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AAKASH INSTITUTE ENGLISH-WORK, ENERGY AND POWER-Assignment (SECTION - A)
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