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The potential energy of a particle in a ...

The potential energy of a particle in a force field is `U=(A)/(r^(2))-(B)/(r)` ,where A and B are positive constants and r is the distance of particle from the centre of the field. For stable equilibrium, the distance of the particle is

A

`(A)/(B)`

B

`(B)/(A)`

C

`(B)/(2A)`

D

`(2A)/(B)`

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The correct Answer is:
D
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