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The position of a particle is expressed ...

The position of a particle is expressed as ` vecr = ( 4t^(2)hati + 2thatj)` m. where t is time in second. Find the acceleration of the particle.

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`bar(a) = (dbarv)/(dt)`
and `bar(v) = 8thati+2hatj`
`:. (dbarv)/(dt)=(d)/(dt) (8thati+2hatj)`
`= hati (d)/(dt) (8t) +hatj(d)/(dt) (2)`
`(dbarv)/(dt) = 8hatj+0hatj`
`= 8hatj ms^(-2)`
Hence the particle has a constant acceleration of magnitude 8 m/`s^(2)` in positive x - direction .
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