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A stone is thrown with a speed of 10 ms^...

A stone is thrown with a speed of `10 ms^(-1)` at an angle of projection `60^(@)`. Find its height above the point of projection when it is at a horizontal distance of 3m from the thrower ? (Take `g = 10 ms^(-2)`)

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To solve the problem step by step, we will use the equations of projectile motion. ### Step 1: Identify the given values - Initial speed (u) = 10 m/s - Angle of projection (θ) = 60° - Horizontal distance (x) = 3 m - Acceleration due to gravity (g) = 10 m/s² ...
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