At the topmost point of its path, a projectile has acceleration of magntiude

Options

A. 0
B. g
C. `(g)/(2)`
D. `(g)/(sqrt(2))`

Answer

To solve the problem regarding the acceleration of a projectile at the topmost point of its path, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the Motion of a Projectile**:
- A projectile is an object that is thrown into the air with an initial velocity at a certain angle (θ) with respect to the horizontal. It follows a parabolic trajectory due to the influence of gravity.

2. **Identifying the Topmost Point**:
- The topmost point of the projectile's path is known as the maximum height (H). At this point, the vertical component of the velocity becomes zero, but the projectile is still under the influence of gravity.

3. **Acceleration Due to Gravity**:
- The only force acting on the projectile (after it has been launched) is the gravitational force, which acts downward. The acceleration due to gravity (g) is approximately 9.81 m/s² and is directed downward.

4. **Magnitude of Acceleration at Maximum Height**:
- At the maximum height, even though the vertical component of the velocity is zero, the acceleration due to gravity remains constant and acts downward. Therefore, the magnitude of the acceleration at this point is equal to the magnitude of gravitational acceleration, which is g.

5. **Conclusion**:
- Thus, the magnitude of the acceleration of the projectile at the topmost point of its path is g.

### Final Answer:
The magnitude of the acceleration at the topmost point of its path is **g** (approximately 9.81 m/s²).

---