Home
Class 12
PHYSICS
A car with a vertical windshield moves i...

A car with a vertical windshield moves in a rain storm at a speed of 40 km/hr. The rain drops fall vertically with constant speed of 20 m/s. The angle at which rain drops strike the windshield is -

A

`tan^(-1)"" (5)/(9)`

B

`tan^(-1) ""(9)/(5)`

C

`tan^(-1) ""(3)/(2)`

D

`tan^(-1)""(2)/(3)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the angle at which raindrops strike the windshield of a car moving in a rainstorm, we can follow these steps: ### Step 1: Identify the velocities - The car is moving at a speed of 40 km/hr. - The raindrops are falling vertically at a speed of 20 m/s. ### Step 2: Convert the car's speed to m/s To convert the speed of the car from km/hr to m/s, we use the conversion factor: \[ 1 \text{ km/hr} = \frac{1}{3.6} \text{ m/s} \] Thus, \[ 40 \text{ km/hr} = 40 \times \frac{1}{3.6} \text{ m/s} \approx 11.11 \text{ m/s} \] ### Step 3: Set up the velocity vectors - The velocity of the rain (falling vertically) can be represented as: \[ \vec{V}_{rain} = 0 \hat{i} - 20 \hat{j} \text{ m/s} \] - The velocity of the car (moving horizontally) can be represented as: \[ \vec{V}_{car} = 11.11 \hat{i} + 0 \hat{j} \text{ m/s} \] ### Step 4: Find the relative velocity of rain with respect to the car The relative velocity of the rain with respect to the car is given by: \[ \vec{V}_{relative} = \vec{V}_{rain} - \vec{V}_{car} \] Substituting the vectors: \[ \vec{V}_{relative} = (0 \hat{i} - 20 \hat{j}) - (11.11 \hat{i} + 0 \hat{j}) = -11.11 \hat{i} - 20 \hat{j} \text{ m/s} \] ### Step 5: Calculate the angle of impact To find the angle \(\theta\) at which the raindrops strike the windshield, we can use the tangent function: \[ \tan(\theta) = \frac{\text{opposite}}{\text{adjacent}} = \frac{|\text{velocity in } \hat{j}|}{|\text{velocity in } \hat{i}|} \] Substituting the values: \[ \tan(\theta) = \frac{20}{11.11} \] ### Step 6: Calculate \(\theta\) Now, we can find \(\theta\) using the arctangent function: \[ \theta = \tan^{-1}\left(\frac{20}{11.11}\right) \] ### Step 7: Final Calculation Using a calculator: \[ \theta \approx \tan^{-1}(1.8) \approx 60.95^\circ \] ### Conclusion Thus, the angle at which the raindrops strike the windshield is approximately \(60.95^\circ\). ---
Promotional Banner

Similar Questions

Explore conceptually related problems

A man is walking on a level road at a speed of 3.0 km/h. Rain drops fall vertically wth a sped of 4.0 km/h. Find the velocity of the raindrops with respect to the man.

A man standing still finds rain pouring at angle 30^(@) with vertical , when he starts walking forward at a speed of 4Kmph it appears to him that rain pours vertically down. When he runs at triple the speed, what is the angle at which rain appers to pour ?

To a man going with a speed of 5 ms^-1 , rain appears to be falling vertically. If the actual speed of rain is 10 m s^-1 , then what is the angle made by rain with the vertical ?

The mean pressure is (6K)/5 , which rain renders to vertical windshield of automobile, moving with constant velocity of magnitude v=12m//s . Consider that raindros fall vertically with speed u=5m//s . The intensity of rainfall deposits h=2cm of sediments in time tau=1 minute: [ rho=10^(3)kg//m^(3)) is the density of liquid] (Assume collisions are inelastic). Calculate K .

A man walking with a speed of 3 km/h finds the rain drops falling vertically downwards. When the man increases his speed to 6km/h he find that the rain drops are falling making an angle of 30^(@) with the vertical . Find the speed of the rain drops ( in km/h)

A man is moving due east with a speed 1 km/hr and rain is falling vertically with a speed sqrt(3) km/hr. At what angle from vertical the man has to hold his umbrella to keep the rain away. Also find the speed of rain drops w.r.t. man.

A man sitting in a bus travelling in a direction from west to east with a speed of 40km//h observes that the rain-drops are falling vertically down. To the another man standing on ground the rain will appear

To a stationary man, rain appears to be falling at his back at an angle 30^@ with the vertical. As he starts moving forward with a speed of 0.5 m s^-1 , he finds that the rain is falling vertically. The speed of rain with respect to the moving man is.

To a stationary man, rain appears to be falling at his back at an angle 30^@ with the vertical. As he starts moving forward with a speed of 0.5 m s^-1 , he finds that the rain is falling vertically. The speed of rain with respect to the stationary man is.

The terminal speed v of a rain water drop in air is :