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Two boys are standing at the ends A and ...

Two boys are standing at the ends A and B of a ground where AB = a. The boy at B starts running in a direction perpendicular to AB with velocity `upsuilon_(1)`. The boy at A starts running simultaneously with velocity `upsilon` and catches the other boy in a time t,where t is

A

`(a)/(sqrt(v^(2)+v_(1)^(2)))`

B

`sqrt(a^(2)/(v^(2)-v_(1)^(2)))`

C

`(a)/((v-v_(1)))`

D

`(a)/((v+v_(1)))`

Text Solution

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The correct Answer is:
B
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