Calculate the number of atoms in
(1) 1 mole of nitrogen `N_(2)`
(2) 1 mole of phosphorous molecules `P_(4)`.
(3) 0.05 g of water

Explanation

(i) 1 mole of nitrogen contains `6.02 xx 10^(23)` molecules i.e. two mole atoms or `1.2046 xx 10^(24)` atoms of nitrogen.
(ii) 1 mole of phosphorous contains `6.02 xx 10^(23)` molecules or `4 xx 6.02 xx 10^(23)` atoms i.e., `2.4092 xx 10^(24)` atoms.
(iii) 18 g of water contains 1 mole of molecules or 3 mole atoms (2 mole atoms of hydrogen and 1 mole atoms of oxygen).
So, Number of atoms in 0.05 g `"water" = (3 xx 6.02 xx 10^(23) xx 0.05)/(18)= 0.05016 xx 10^(23)= 5.016 xx 10^(21) "atoms"`