How many gram of oxygen `(O_(2))` is required to completely react with 0.200 g of hydrogen `(H_(2))` to yield water `(H_(2)O)` ? Also calculate the amount of water formed (molecular mass H = 2, O = 32).

Explanation

To solve the problem, we need to determine how many grams of oxygen `(O2)` are required to completely react with 0.200 g of hydrogen `(H2)` to yield water `(H2O)`, and also calculate the amount of water formed.

### Step-by-Step Solution:

**Step 1: Write down the given data.**
- Mass of hydrogen (H2) = 0.200 g
- Molecular mass of hydrogen (H) = 2 g/mol
- Molecular mass of oxygen (O) = 32 g/mol
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