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How much magnesium sulphide can be obtai...

How much magnesium sulphide can be obtained from `2.00 g` of `Mg` and `2.00 g` of `S` by the reaction.
`Mg + S rarr MgS`. Which is the limiting reagent? Calculate the amount of one of the reactants which remains unreacted?

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We shall convert the masses into moles
`2.00 g "of "Mg = (2.00)/(24)= 0.0833 "moles of Mg"`
`2.00 g of S = (2.00)/(32)= 0.0625 "moles of S"`
From the equation, `Mg + S to MgS`
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