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A solution is prepared by dissolving 1.0...

A solution is prepared by dissolving 1.0g of NaOH in water to get 250 ml of solution. Calculato its molarity.

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To calculate the molarity of the NaOH solution, we will follow these steps: ### Step 1: Calculate the number of moles of NaOH The formula to calculate the number of moles is: \[ \text{Number of moles} = \frac{\text{Given mass}}{\text{Molar mass}} \] Given mass of NaOH = 1.0 g ...
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AAKASH INSTITUTE ENGLISH-SOME BASIC CONCEPT OF CHEMISTRY-ASSIGNMENT( SECTION - D) Assertion-Reason Type Questions
  1. A solution is prepared by dissolving 1.0g of NaOH in water to get 250 ...

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  2. A: 1 "a.m.u." = 1.66 xx 10^(-24) gram. R: Actual mass of one atom of...

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  3. A: Unit of specific gravity is gram-"cc"^(-1) R: Specific gravity i...

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  4. A: Number of atoms in 2 mole of NH(3) is equal to number of atoms in 4...

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  5. A: In the reaction 2NaOH + H(3)PO(4) to Na(2)HPO(4) + 2H(2)O equi...

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  6. A: Mass of 1 gram molecule of H(2)SO(4) is 98 gram. R: One gram atom...

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  7. A: One mole of sucrose-reacts completely with oxygen produces 268.8 li...

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  8. A: In the reaction, 2NaOH+H(2)SO(4) to Na(2)SO(4) + 2H(2)O equival...

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  9. A: When 4 moles of H(2) reacts with 2 moles of O(2), then 4. moles of ...

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  10. A: 50 ml, decinormal HCl when mixed with 50 ml, decinormal H(2) SO(4),...

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  11. A : 50 ml, decimolar H(2) SO(4) when mixed with 50 ml, decimolar NaOH,...

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  12. A : Ratio of empirical formula mass and molecular formula mass must be...

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  13. A: For a given solution (density 1 gm//ml), molality is greater than m...

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  14. A: 1 gram of salt in 1 m^(3) of solution has concentration of 1 ppm. ...

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  15. A: Total charge on N(A) ions of CO(3)^(2-) is 1.93 xx 10^(5) coulomb. ...

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  16. A: Number of ions in 9 gram of NH(4)^(+) is equal to Avogadro's number...

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