How many gram equivalents of `H_(2)SO_(4)` are present in 200 ml of `(N)/(10) H_(2)SO_(4)` solution?

Explanation

To find the number of gram equivalents of \( H_2SO_4 \) present in 200 ml of \( \frac{N}{10} \) \( H_2SO_4 \) solution, we can follow these steps:

### Step 1: Understand Normality
Normality (N) is defined as the number of gram equivalents of solute per liter of solution. In this case, we have a \( \frac{N}{10} \) solution of \( H_2SO_4 \).

### Step 2: Convert Normality to Gram Equivalents
The normality of the solution is given as \( \frac{1}{10} \) N. This means that in 1 liter (1000 ml) of the solution, there are \( \frac{1}{10} \) gram equivalents of \( H_2SO_4 \).

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