`200 ml (N)/(10)` `H_(2)SO_(4)` is mixed into `300 ml (N)/(100) NaOH`. Calculate normality of resulting mixture.

Explanation

To solve the problem of calculating the normality of the resulting mixture when 200 ml of \( \frac{N}{10} \) \( H_2SO_4 \) is mixed with 300 ml of \( \frac{N}{100} \) \( NaOH \), we can follow these steps:

### Step 1: Calculate the gram equivalents of \( H_2SO_4 \)

1. **Normality of \( H_2SO_4 \)**: Given as \( \frac{N}{10} \).
2. **Volume of \( H_2SO_4 \)**: Given as 200 ml, which we convert to liters:
\[
\text{Volume in liters} = \frac{200 \, \text{ml}}{1000} = 0.2 \, \text{L}
...