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50.0 kg of N(2) (g) and 10.0 kg of H(2) ...

50.0 kg of `N_(2)` (g) and 10.0 kg of `H_(2)` (g) are mixed to produce `NH_(3)` (g). Calculate the amount of` NH_(3)` (g) formed. Identify the limiting reagent in the production of NH3 in this situation

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`3.30 xx 10^(3)` mol `NH_(3)` is obtained.
Dihydrogen is the limiting agent.
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