If the weight of metal chloride is x gm containing y gm of metal, the equivalent weight of metal will be :-

Options

A. `E= (x)/(y) xx 35.5`
B. `E= (8(y-x))/(x)`
C. `E= (y)/(x-y) xx 35.5`
D. `E= (8(x-y))/(y)`

Answer

To find the equivalent weight of the metal in the metal chloride, we can follow these steps:

### Step 1: Identify the given values
- Weight of metal chloride = \( x \) grams
- Weight of metal = \( y \) grams

### Step 2: Calculate the weight of chlorine
The weight of chlorine in the metal chloride can be calculated as:
\[ \text{Weight of chlorine} = \text{Weight of metal chloride} - \text{Weight of metal} = x - y \text{ grams} \]

### Step 3: Understand the formula for equivalent weight
The equivalent weight of a substance can be defined using the formula:
\[ \frac{\text{Equivalent weight of metal}}{\text{Equivalent weight of chlorine}} = \frac{\text{Weight of metal}}{\text{Weight of chlorine}} \]

### Step 4: Calculate the equivalent weight of chlorine
The equivalent weight of chlorine (Cl) can be calculated using its atomic mass and valency:
\[ \text{Equivalent weight of chlorine} = \frac{\text{Atomic mass of Cl}}{\text{Valency of Cl}} = \frac{35.5}{1} = 35.5 \text{ grams} \]

### Step 5: Substitute the values into the formula
Now substituting the values into the formula:
\[ \frac{E}{35.5} = \frac{y}{x - y} \]
Where \( E \) is the equivalent weight of the metal.

### Step 6: Solve for the equivalent weight of the metal
Rearranging the equation to solve for \( E \):
\[ E = \frac{y}{x - y} \times 35.5 \]

### Step 7: Final expression
Thus, the equivalent weight of the metal is:
\[ E = \frac{y}{x - y} \times 35.5 \]

### Conclusion
The equivalent weight of the metal in the metal chloride is given by the expression:
\[ E = \frac{y}{x - y} \times 35.5 \]

### Answer
The correct option is **C: \( E = \frac{y}{x - y} \times 35.5 \)**.

---