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If the weight of metal oxide is x g cont...

If the weight of metal oxide is x g containing y g of oxygen, the equivalent weight of metal will be

A

`E= (8x)/(y)`

B

`E= (8(y-x))/(x)`

C

`E= (y)/(8)`

D

`E= (8(x-y))/(y)`

Text Solution

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The correct Answer is:
To find the equivalent weight of the metal in the metal oxide, we can follow these steps: ### Step 1: Understand the Given Information We are given: - Weight of metal oxide = \( x \) g - Weight of oxygen in the metal oxide = \( y \) g ### Step 2: Calculate the Weight of the Metal The weight of the metal can be calculated by subtracting the weight of oxygen from the weight of the metal oxide: \[ \text{Weight of metal} = \text{Weight of metal oxide} - \text{Weight of oxygen} \] \[ \text{Weight of metal} = x - y \text{ g} \] ### Step 3: Determine the Equivalent Weight of Oxygen The equivalent weight of oxygen is known to be 8 g. This is because: \[ \text{Equivalent weight of oxygen} = \frac{\text{Molecular weight of oxygen}}{\text{Valency of oxygen}} = \frac{16}{2} = 8 \text{ g} \] ### Step 4: Set Up the Relation for Equivalent Weights Using the relation for equivalent weights: \[ \frac{\text{Equivalent weight of metal}}{\text{Equivalent weight of oxygen}} = \frac{\text{Weight of metal}}{\text{Weight of oxygen}} \] Substituting the known values: \[ \frac{E}{8} = \frac{x - y}{y} \] ### Step 5: Solve for the Equivalent Weight of the Metal Rearranging the equation to solve for \( E \): \[ E = 8 \times \frac{x - y}{y} \] Thus, we can express the equivalent weight of the metal as: \[ E = \frac{8(x - y)}{y} \] ### Conclusion The equivalent weight of the metal is given by the formula: \[ E = 8 \times \frac{x - y}{y} \]
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