In Boh'r series of lines of hydrogen spectrum, the third line from the red corresponds to which one of the following inter orbit jumps of the electron for Boh'r orbit in an atom of hydrogen ?

Options

A. ` 3 to 1`
B. `5 to2`
C. `2 to 5`
D. `3 to 2`

Answer

To solve the question regarding the third line from the red end of the hydrogen spectrum in the Balmer series, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Balmer Series**: The Balmer series corresponds to the transitions of electrons in a hydrogen atom where the final energy level (n1) is 2. The initial energy level (n2) can be 3, 4, 5, etc.

2. **Identify the Red Line**: The red line in the Balmer series is the first line observed, which corresponds to the transition of an electron from n2 = 3 to n1 = 2.

3. **Determine the Subsequent Lines**:
- The **first line** (red) corresponds to the transition from n2 = 3 to n1 = 2.
- The **second line** corresponds to the transition from n2 = 4 to n1 = 2.
- The **third line** corresponds to the transition from n2 = 5 to n1 = 2.

4. **Conclusion**: Therefore, the third line from the red in the Balmer series corresponds to the transition of the electron from the fifth orbit (n2 = 5) to the second orbit (n1 = 2).

### Final Answer:
The third line from the red in the Balmer series corresponds to the transition from n2 = 5 to n1 = 2.

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