Home
Class 12
CHEMISTRY
The ratio of the energy required to remo...

The ratio of the energy required to remove an electron from the first three Bohr's orbit of Hydrogen atom is

A

`3:2:1`

B

`9:4:1`

C

`36 :9:4`

D

`1 :4 :9`

Text Solution

AI Generated Solution

The correct Answer is:
To find the ratio of the energy required to remove an electron from the first three Bohr orbits of a hydrogen atom, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Energy Formula**: The energy of an electron in the nth orbit of a hydrogen atom is given by the formula: \[ E_n = -\frac{13.6 \, \text{eV}}{n^2} \] where \( n \) is the principal quantum number. 2. **Calculate the Energy for Each Orbit**: - For the first orbit (\( n = 1 \)): \[ E_1 = -\frac{13.6 \, \text{eV}}{1^2} = -13.6 \, \text{eV} \] - For the second orbit (\( n = 2 \)): \[ E_2 = -\frac{13.6 \, \text{eV}}{2^2} = -\frac{13.6}{4} = -3.4 \, \text{eV} \] - For the third orbit (\( n = 3 \)): \[ E_3 = -\frac{13.6 \, \text{eV}}{3^2} = -\frac{13.6}{9} \approx -1.51 \, \text{eV} \] 3. **Determine the Ionization Energy**: The energy required to remove an electron (ionization energy) from each orbit is the negative of the energy in that orbit: - Ionization energy from the first orbit: \[ I_1 = -E_1 = 13.6 \, \text{eV} \] - Ionization energy from the second orbit: \[ I_2 = -E_2 = 3.4 \, \text{eV} \] - Ionization energy from the third orbit: \[ I_3 = -E_3 = \frac{13.6}{9} \approx 1.51 \, \text{eV} \] 4. **Set Up the Ratio**: Now we can set up the ratio of the ionization energies: \[ I_1 : I_2 : I_3 = 13.6 : 3.4 : \frac{13.6}{9} \] 5. **Simplify the Ratio**: To simplify the ratio, we can express each term with a common denominator. The common denominator for 4 and 9 is 36: - Multiply each term by 36: \[ 13.6 \times 36 : 3.4 \times 36 : \frac{13.6}{9} \times 36 \] - This gives: \[ 489.6 : 122.4 : 54.4 \] - Dividing each term by 13.6 gives: \[ 36 : 9 : 4 \] 6. **Final Result**: The final ratio of the energy required to remove an electron from the first three Bohr orbits of a hydrogen atom is: \[ \text{Ratio} = 36 : 9 : 4 \] ### Answer: The answer is option C: \( 36 : 9 : 4 \).
Promotional Banner

Topper's Solved these Questions

  • STRUCTURE OF ATOM

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT (SECTION -D) Assertion-Reason Type Questions|15 Videos
  • STRUCTURE OF ATOM

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT (SECTION -B) Objective type questions|34 Videos
  • STATES OF MATTER

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT (SECTION-D)|14 Videos
  • STRUCTURE OF ATOM

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT ( SECTION -J) Aakash Challengers Questions|12 Videos

Similar Questions

Explore conceptually related problems

The energy that is needed to remove an electron from the 1st Bohr orbit or Hydrogen atom is

Radius of Bohr's orbit of hydrogen atom is

Radius of Bohr's orbit of hydrogen atom is

What is the energy required to remove an electron from second orbit of hydrogen atom ?

What is the energy required to remove an electron from second orbit of hydrogen atom ?

The ionization energy of the electron in the lowest orbit of hydrogen atom is 13.6 eV. The energies required in eV to remove an electron from three lowest energy orbits of hydrogen atom respectively are

The ionisation potential of hydrogen atom is 13.6 volt. The energy required to remove an electron in the n = 2 state of the hydrogen atom is

The ionisation potential of hydrogen atom is 13.6 eV . The energy required to remove an electron in the n = 2 state of the hydrogen atom is

Calculate the velocity of an electron in the first Bohr orbit of a hydrogen atom

Determine wavelength of electron in 4th Bohr's orbit of hydrogen atom

AAKASH INSTITUTE ENGLISH-STRUCTURE OF ATOM-ASSIGNMENT (SECTION -C) Previous Years Questions
  1. A micorscope using suitable photons is employed an electron in an atom...

    Text Solution

    |

  2. Orientation of orbitals is given by

    Text Solution

    |

  3. The energy of second Bohr orbit of the hydrogen atom is -328 kJ "mol"...

    Text Solution

    |

  4. Uncertainty in position of an electron (mass of an electron is =9.1x...

    Text Solution

    |

  5. Bohr radium for the hydrogen atom (n=1) is approximately 0.530 Å. The ...

    Text Solution

    |

  6. In Bohr 's model of hydrogen when an electron jumps from n=1 to n=3 ho...

    Text Solution

    |

  7. The electronic configuration of gadolinium (Atomic number 64) is

    Text Solution

    |

  8. The ion that is isoelectronic with CO is

    Text Solution

    |

  9. Bohr's radius for the H-atom (n =1) is approximately 0.53 Ã…. The ra...

    Text Solution

    |

  10. The position of both an electron and a helium atom is known within 1.0...

    Text Solution

    |

  11. Which of the following electron configurations is correct for iron,(at...

    Text Solution

    |

  12. Which of the following has maximum of unpaired d- electrons ?

    Text Solution

    |

  13. Who modified Bohr's theory by introducing elliptical orbits for el...

    Text Solution

    |

  14. The de-Broglie wavelength of a particle with mass 1 g and velocity 100...

    Text Solution

    |

  15. The following quantum numbers are possible for how many orbital (s) n...

    Text Solution

    |

  16. The frequency of radiation emiited when the electron falls n =...

    Text Solution

    |

  17. Which one of the following ions has electronic configuration [Ar]3d^(6...

    Text Solution

    |

  18. which of the following is not among shortcomings of bohr 's mod...

    Text Solution

    |

  19. Number of spectral lines falling Balmer series when electrons a...

    Text Solution

    |

  20. The ratio of the energy required to remove an electron from the first ...

    Text Solution

    |