Home
Class 12
CHEMISTRY
The successive ionization energies for e...

The successive ionization energies for element X is given below
`IE_(1)` : 250 kJ `"mo"^(-1)`
`IE_(2)` : 820 kJ `"mo"^(-1)`
`IE_(3)` : 1100 kJ `"mo"^(-1)`
`IE_(4)` : 1400 kJ `"mo"^(-1)`
Find out the number of valence electrons for the elements X.

A

3

B

4

C

2

D

1

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Similar Questions

Explore conceptually related problems

The element having lowest IE_(1)

The element having lowest IE_(1)

The first four I.E. values of an element are 284, 412, 656 and 3210 kJ mol^(-1) . The number of valence electrons in the element are:

Which among the following elements have the lowest value of IE_(1) ?

Which among the following elements have lowest value of IE_1 ?

The five successive ionisation energies energies of an element 'X' are 800, 1427, 2658, 25024 and 32824 "KJ mole"^(-1) respectively . The valency of 'X' is :

IE_(2) for an element is inveriably higher than IE_(1) because

IE_(2) for an element is inveriably higher than IE_(1) because

Consider the successive ionisation energy for an element 'A' . IE_(1) , IE_(2) , IE_(3) , IE_(4), IE_(5) are 100 eV , 150 eV , 181eV , 2000 eV , 2200 eV . Select correct statement (s) for element 'A' : a)Element 'A' may be metal b)Element 'A' may from trivalent cation c)Oxide of element 'A' may be amphoteric d)Element 'A' may be non-metal

In 3d , 4d and 5d series which element is expected to have highest IE_(1) ?