Which of the following is correct for `XeO_(2)F_(2)` and `PCl_(5)` ?

Options

A. Both have same hybridisation and shape
B. Both have same hybridisation but different geometry
C. Both have different hybridisation but same shape
D. both have same hybridisation but different shape

Answer

To determine the correct statement regarding the hybridization and shape of `XeO2F2` and `PCl5`, we will follow these steps:

### Step 1: Determine the hybridization of `XeO2F2`
1. Identify the central atom: Xenon (Xe).
2. Count the valence electrons of Xenon: Xe has 8 valence electrons.
3. Count the number of monovalent atoms attached: There are 2 fluorine (F) atoms and 2 oxygen (O) atoms (considering the double bonds as 1 bond each).
4. Use the formula for hybridization:
\[ \text{Hybridization} = \frac{1}{2} \left( V + M + A - C \right) \]
where:
- \( V \) = number of valence electrons of the central atom (8 for Xe)
- \( M \) = number of monovalent atoms (4 for 2 F and 2 O)
- \( A \) = charge from anions (0, as there are no anions)
- \( C \) = charge from cations (0, as there are no cations)

Plugging in the values:
\[ \text{Hybridization} = \frac{1}{2} (8 + 4 + 0 - 0) = \frac{12}{2} = 6 \]
This indicates that the hybridization is \( sp^3d \).

### Step 2: Determine the shape of `XeO2F2`
1. Count the bond pairs and lone pairs:
- There are 4 bond pairs (2 from F and 2 from O) and 1 lone pair.
2. The geometry based on the steric number (5) is trigonal bipyramidal.
3. The shape, considering the lone pair, is seesaw.

### Step 3: Determine the hybridization of `PCl5`
1. Identify the central atom: Phosphorus (P).
2. Count the valence electrons of Phosphorus: P has 5 valence electrons.
3. Count the number of monovalent atoms attached: There are 5 chlorine (Cl) atoms.
4. Use the hybridization formula:
\[ \text{Hybridization} = \frac{1}{2} (5 + 5 + 0 - 0) = \frac{10}{2} = 5 \]
This indicates that the hybridization is also \( sp^3d \).

### Step 4: Determine the shape of `PCl5`
1. Count the bond pairs and lone pairs:
- There are 5 bond pairs and 0 lone pairs.
2. The geometry based on the steric number (5) is trigonal bipyramidal.
3. The shape is also trigonal bipyramidal.

### Conclusion
- For `XeO2F2`: Hybridization is \( sp^3d \) and shape is seesaw.
- For `PCl5`: Hybridization is \( sp^3d \) and shape is trigonal bipyramidal.

### Final Answer
The correct statement is: **Both have same hybridization but different shape.**