In the given structure of a compound, the correct various bond moments direction involving atoms are shown as

Options

A. `Br = N` = `CH_(2) = SiH_(2) = CH_(2) = O = CH_(3)`
B. Br = N = `CH_(2) = SiH_(2) = CH_(2) = O=CH_(3)`
C. `Br = N = CH_(2) = SiH_(2) = CH_(2) = O = CH_(3)`
D. `Br = N = CH_(z) = SiH_(2) = CH_(2) = O = CH_(3)`

Answer

To solve the question regarding the direction of bond moments in a compound, we will follow these steps:

### Step 1: Identify the Atoms and Their Electronegativity
First, we need to identify the atoms involved in the compound and their respective electronegativities. The given atoms are Nitrogen (N), Oxygen (O), Silicon (Si), Bromine (Br), and Carbon (C).

### Step 2: List the Electronegativity Values
Next, we will list the electronegativity values of these atoms:
- Oxygen (O): 3.44
- Nitrogen (N): 3.04
- Bromine (Br): 2.96
- Carbon (C): 2.5
- Silicon (Si): 1.9

### Step 3: Determine the Electronegativity Order
Based on the electronegativity values, we can arrange the atoms in order of decreasing electronegativity:
1. O (3.44)
2. N (3.04)
3. Br (2.96)
4. C (2.5)
5. Si (1.9)

### Step 4: Identify the Direction of Bond Dipole Moments
The bond dipole moment direction is always towards the more electronegative atom. Therefore, we can determine the bond moments for the pairs:
- O → N
- N → Br
- Br → C
- C → Si

### Step 5: Conclusion
From the above analysis, we can conclude that the correct direction of bond moments will be towards the more electronegative atom in each bond. Therefore, the correct option that represents the bond moment directions involving these atoms is option 3, which states that the bond moment direction is from Br to Si, and from Si to C.

### Final Answer
The correct answer is option 3.

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