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In the following questions, a statement ...

In the following questions, a statement of assertion (A) is followed by a statement of reason (R )
A : `N_(2)` CO and `CN^(-)` are having same bond order.
R: Isoelectronic species always have same bond order .

A

If both Assertion & Reason are true and the reason is the correct explanation of the assertion, then mark (1)

B

If both Assertion & Reason are true but the reason is not the correct explanation of the assertion, then mark (2)

C

If Assertion is true statement but Reason is false, then mark (3)

D

If both Assertion and Reason are false statements , then mark (4).

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the assertion (A) and reason (R) about the bond order of \(N_2\), \(CO\), and \(CN^-\), we will follow these steps: ### Step 1: Determine the number of electrons in each species - **For \(N_2\)**: Nitrogen has an atomic number of 7. Thus, \(N_2\) has \(7 + 7 = 14\) electrons. - **For \(CO\)**: Carbon has 6 electrons and Oxygen has 8 electrons. Therefore, \(CO\) has \(6 + 8 = 14\) electrons. - **For \(CN^-\)**: Carbon has 6 electrons, Nitrogen has 7 electrons, and there is an extra electron due to the negative charge. Thus, \(CN^-\) has \(6 + 7 + 1 = 14\) electrons. ### Step 2: Confirm that all three species are isoelectronic Since all three species \(N_2\), \(CO\), and \(CN^-\) have the same number of electrons (14), they are isoelectronic. ### Step 3: Calculate the bond order for each species using Molecular Orbital Theory The bond order can be calculated using the formula: \[ \text{Bond Order} = \frac{1}{2} \times (\text{Number of electrons in bonding orbitals} - \text{Number of electrons in antibonding orbitals}) \] 1. **Molecular Orbital Configuration**: - For \(N_2\): The configuration is \((\sigma_{1s})^2 (\sigma^*_{1s})^2 (\sigma_{2s})^2 (\sigma^*_{2s})^2 (\sigma_{2p_z})^2 (\pi_{2p_x})^2 (\pi_{2p_y})^2\) - For \(CO\): The configuration is similar to \(N_2\) due to the same number of electrons. - For \(CN^-\): The configuration will also be similar, with the same filling. 2. **Counting Electrons**: - **Bonding Orbitals**: 10 electrons (2 in \(\sigma_{1s}\), 2 in \(\sigma_{2s}\), 2 in \(\sigma_{2p_z}\), 4 in \(\pi_{2p_x}\) and \(\pi_{2p_y}\)) - **Antibonding Orbitals**: 4 electrons (2 in \(\sigma^*_{1s}\) and 2 in \(\sigma^*_{2s}\)) 3. **Calculating Bond Order**: \[ \text{Bond Order} = \frac{1}{2} \times (10 - 4) = \frac{1}{2} \times 6 = 3 \] ### Step 4: Conclusion Since the bond order for \(N_2\), \(CO\), and \(CN^-\) is 3, the assertion (A) is true. The reason (R) states that isoelectronic species always have the same bond order, which is also true. Therefore, both the assertion and reason are correct, and the reason is a correct explanation for the assertion. ### Final Answer Both assertion and reason are true, and the reason is the correct explanation for the assertion. ---
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