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Determine the enthalpy change for the gi...

Determine the enthalpy change for the given reaction.
`CH_(4) (g) + Cl_(2) (g) rightarrow CH_(3) Cl(g) + HCI (g)`
Bond energies are given as follows:
`C-H = 412 kJ mol^(-1)`
`C-CI = 338 kJ mol^(-1)`
`CI-CI = 242 kJ mol^(-1)`
`H-CI = 431 kJ mol^(-1)`.

Text Solution

AI Generated Solution

To determine the enthalpy change (ΔH) for the reaction: \[ \text{CH}_4 (g) + \text{Cl}_2 (g) \rightarrow \text{CH}_3\text{Cl} (g) + \text{HCl} (g) \] we will use the bond energies provided. The enthalpy change can be calculated using the formula: \[ \Delta H = \text{Energy of bonds broken} - \text{Energy of bonds formed} ...
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