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180 J of work is done on the system and ...

180 J of work is done on the system and at the same time 120 J of heat is given out. What is the change in the internal energy?

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To solve the problem, we will use the first law of thermodynamics, which states: \[ \Delta U = Q + W \] Where: - \(\Delta U\) is the change in internal energy, ...
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