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Certain reaction is at equilibrium at 82...

Certain reaction is at equilibrium at `82^(@)C` and `Delta H` for this reaction is `21.3 kJ mol^(-1)`. What would be the value of `Delta S(in JK^(-1) mol^(-1))` for the reaction.

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To find the value of ΔS (entropy change) for the reaction at equilibrium, we will follow these steps: ### Step 1: Convert Temperature to Kelvin The temperature is given as 82°C. To convert this to Kelvin, we use the formula: \[ T(K) = T(°C) + 273 \] So, \[ T = 82 + 273 = 355 \, K \] ...
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