The temperature of 15 ml of a strong acid increases by `2^(@)C` when 15 ml of a strong base is added to it. If 5 ml of each are mixed, temperature should increase by

Options

A. `0.6^(@)C`
B. `0.3 ^(@)C`
C. `2^(@)C`
D. `6^(@)C`

Answer

To solve the problem, we need to understand the relationship between the volumes of the strong acid and strong base, the heat of neutralization, and the resulting temperature change.

### Step-by-Step Solution:

1. **Understanding the Initial Condition**:
- We have 15 ml of a strong acid and 15 ml of a strong base mixed together.
- The temperature increase observed when these two are mixed is 2°C.

2. **Heat of Neutralization**:
- For strong acids and strong bases, the heat of neutralization is constant. This means that regardless of the volumes mixed, the heat released during the neutralization reaction remains the same.
- The heat of neutralization for strong acid and strong base is approximately 57.1 kJ/mol.

3. **Mixing Equal Volumes**:
- When we mix equal volumes of a strong acid and a strong base, the temperature change will be the same, regardless of the volume, as long as the volumes are equal.
- This is because the heat of neutralization does not change with the volume, and thus the temperature change resulting from the reaction will also remain constant.

4. **Calculating for 5 ml of Each**:
- Now, we are mixing 5 ml of the strong acid with 5 ml of the strong base.
- Since we are still mixing equal volumes (5 ml of acid and 5 ml of base), the heat of neutralization remains the same as in the previous case.

5. **Conclusion**:
- Therefore, the temperature increase when 5 ml of each is mixed will also be the same as when 15 ml of each was mixed, which is 2°C.

### Final Answer:
The temperature should increase by **2°C** when 5 ml of each strong acid and strong base are mixed.

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