The dissociation constant of a base MOH is `4xx10^(-6)` then calculate the dissociation constant of its conjugate acid

Explanation

To find the dissociation constant of the conjugate acid of the base MOH, we will use the relationship between the dissociation constants of a conjugate acid-base pair. The relationship is given by the equation:

\[ K_a \times K_b = K_w \]

Where:
- \( K_a \) is the dissociation constant of the conjugate acid,
- \( K_b \) is the dissociation constant of the base,
- \( K_w \) is the ion product of water, which at 25°C is \( 1.0 \times 10^{-14} \).
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