The dissociation constant of 0.01 M `CH_3COOH "is" 1.8 xx 10^(-5)`, then calculate the dissociation constant of its conjugate base `(CH_3COO^-)`

Explanation

To find the dissociation constant (Kb) of the conjugate base (CH₃COO⁻) of acetic acid (CH₃COOH), we can use the relationship between the dissociation constants of an acid and its conjugate base. Here are the steps to solve the problem:

### Step 1: Identify the given values
- The dissociation constant (Ka) of acetic acid (CH₃COOH) is given as:
\[ K_a = 1.8 \times 10^{-5} \]
- The dissociation constant of water (Kw) is a known value:
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