Home
Class 12
CHEMISTRY
Calculate the degree of hydrolysis of 0....

Calculate the degree of hydrolysis of 0.1 M solution of acetate at 298 k.
Given : `K_a=1.8xx10^(-5)`

Text Solution

AI Generated Solution

To calculate the degree of hydrolysis of a 0.1 M solution of sodium acetate (CH₃COONa) at 298 K, we can follow these steps: ### Step 1: Understand the concept of hydrolysis Sodium acetate is a salt formed from a strong base (sodium hydroxide) and a weak acid (acetic acid). When dissolved in water, it undergoes hydrolysis, which can be represented as: \[ \text{CH}_3\text{COO}^- + \text{H}_2\text{O} \rightleftharpoons \text{CH}_3\text{COOH} + \text{OH}^- \] ### Step 2: Determine the hydrolysis constant (K_h) The hydrolysis constant (K_h) can be calculated using the relationship: ...
Promotional Banner

Topper's Solved these Questions

  • EQUILIBRIUM

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (SECTION-A) (SUBJECTIVE TYPE QUESTIONS(ONE OPTION IS CORRECT)|45 Videos
  • EQUILIBRIUM

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (SECTION-B)(OBJECTIVE TYPE QUESTIONS (ONE OPTION IS CORRECT)|20 Videos
  • ENVIRONMENTAL CHEMISTRY

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT (SECTION-D) (Assertion - Reason Type Questions)|4 Videos
  • GENERAL PRINCIPLES AND PROCESSES OF ISOLATION OF ELEMENTS

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (Section-D) Assertion-Reason Type Question|15 Videos

Similar Questions

Explore conceptually related problems

Calculate the degree of hydrolysis of 0.1 M solution of sodium acetate at 298 K : K_(a) = 1.8 xx 10^(-5) .

Calculate the hydrolysis constant. Degree of hydrolysis and pH of 0.5 M solution of NH_4Cl. ( Given : K_a = 1.78 xx 10 ^(-5) ,K_b= 1.8 xx 10 ^(-5) and K_w = 1.8 xx 10 ^(-14) )

Calculate the degree of hydrolysis of the 0.01 M solution of salt (KF)(Ka(HF)=6.6xx10^(-4)) :-

Calculate the percentage hydrolysis of decinormal solution of ammonium acetate given that k_(a) = 1.75 xx 10^(-5), K_(b) =1.80 xx 10^(-5) and K_(w) = 1.0 xx 10^(-14)

Calculate the percentage hydrolysis of decinormal solution of ammonium acetate given that k_(a) = 1.75 xx 10^(-5), K_(b) =1.80 xx 10^(-5) and K_(w) = 1.0 xx 10^(-14)

Calculate the degree of hydrolysis and pH of 0.2M solution of NH_(4)C1 Given K_(b) for NH_(4)OH is 1.8 xx 10^(-5) .

The degree of hydrolysis of 0.005 M aqueous solution of NaOCN will be ( K_a for HOCN = 4.0xx10^-4 )

Calculate the pH of a solution of ammonium acetate (Given : K_a= 1.78 xx 10 ^(-5) ,K_b= 1.8 xx 10 ^(-5) and K_w = 1.8 xx 10^(-14))

Calculate the hydrolysis constant and degree of hydrolysis of NH_(4) Cl" in " 0.1 M solution . K_(b) = 1.8 xx 10^(-5) . Calculate the concentration of H^(+) ions in the solution .

Calculate the hydrolysis constant. Degree of hydrolysis and pH of a 0.1 M NH_4Cl solution at 25 ^(@) C Given : K_b " for " NH_4OH= 1.8 xx 10^(-5)

AAKASH INSTITUTE ENGLISH-EQUILIBRIUM-ASSIGNMENT (SECTION -D)
  1. Calculate the degree of hydrolysis of 0.1 M solution of acetate at 298...

    Text Solution

    |

  2. A : At higher temperature , Kw of water remains unaltered. R: kw is ...

    Text Solution

    |

  3. A : HCI, HNO3 and H2SO4 are equalty strong acids in water R : Water ...

    Text Solution

    |

  4. A : Increasing the concentration of H2 will increases magnitude of e...

    Text Solution

    |

  5. A : Increasing the temperature , increases [H^+] concentration in wat...

    Text Solution

    |

  6. A : Solution of CH3COONH4 is a buffer solution R: H^+ ion added will...

    Text Solution

    |

  7. A : K(sp) is a constant value for any salt at particular temperature ...

    Text Solution

    |

  8. A : H3O^+ ion from water is also taken in consideration while calcula...

    Text Solution

    |

  9. A : pH of 10^(-8) M HCI solution is approx 6.9 R : HCI is a strong a...

    Text Solution

    |

  10. A : For equilibrium ice hArr water on increasing temperature and pres...

    Text Solution

    |

  11. Assertion: At equilibrium the concentration of all reactants and produ...

    Text Solution

    |

  12. A : pH of 0.1 M HCI solution is less than 0.1 M HCN solution R : In ...

    Text Solution

    |

  13. A : A catalyst does not alter the equilibrium constant of a reaction ...

    Text Solution

    |

  14. A : pH of equimolar solution of NH4 CI and NH4OH does not change when ...

    Text Solution

    |

  15. A: The reaction 2NO(g) +O2(g) hArr 2NO2(g) is favoured in the forwar...

    Text Solution

    |

  16. A : pH of 1 M NaCI solution is 7 at 25^@C. R : pH of this solution d...

    Text Solution

    |

  17. A : CO2 is a Lewis acid. R : H2SO4 is Arrhenius acid as well as Bron...

    Text Solution

    |

  18. A : For H2CO3 K(a1) lt K(a2). R : H2CO3 is weaker acid than HCO3^-

    Text Solution

    |

  19. A : pH of mixture of 0.1 M HCN and 0.05 M NaOH is less than 7 . R : ...

    Text Solution

    |

  20. STATEMENT-1: Solubility of AgCN in NH(3) (aq.), is greater than in pur...

    Text Solution

    |

  21. A : Precipitates formation takes place when K(ip) gt K(sp) . R : K...

    Text Solution

    |