Calcualte the solubility of `M_(2)X_(3)` in pure water, assuming that neither kind of ion reacts with `H_(2)O`. The solubility product of `M_(2)X_(3), K_(sp) = 1.1 xx 10^(-23)`.

Explanation

`{:(A_2X_3,hArr,2A^(+3),+3X^(-2)),(1,"",0,0),(1-s,"",2s,3s):}`
`K_(sp)=[A^(+3)]^2[X^(-2)]^3`
`(2s)^2xx(3s)^3`
`=4s^2xx27s^3`
`=108s^5=1.1xx10^(-23)`
`s=((K_(sp))/(108))^(1//5)=((1.1xx10^(-23))/(108))^(1//5) =10^(-5) mol L^(-1)`