If ionisation constant of an acid (HA) at equilibrium is `1.0xx10^(-8)` then calculate the value of `pK_a and pK_b` (for its conjugate base).

Explanation

To solve the problem of finding the values of \( pK_a \) and \( pK_b \) for the given acid \( HA \) with an ionization constant \( K_a \) of \( 1.0 \times 10^{-8} \), we can follow these steps:

### Step 1: Calculate \( pK_a \)

The formula for calculating \( pK_a \) from \( K_a \) is:

\[
pK_a = -\log(K_a)
...