One litre of `0.05` M HCl was completely neutralized by NaOH. Calcuate the pH of resulting solution

Explanation

To solve the problem of calculating the pH of the resulting solution after neutralization of HCl by NaOH, we can follow these steps:

### Step 1: Determine the moles of HCl
Given that the concentration of HCl is 0.05 M and the volume is 1 L, we can calculate the number of moles of HCl.

\[ \text{Moles of HCl} = \text{Concentration} \times \text{Volume} = 0.05 \, \text{mol/L} \times 1 \, \text{L} = 0.05 \, \text{mol} \]
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