The compound whose `0.1 M` solution is basic is

Options

A. Ammonium acetate
B. Ammonium chloride
C. Ammonium sulphate
D. sodium acetate

Answer

To determine which compound has a 0.1 M solution that is basic, we need to analyze the nature of the compounds provided and their behavior in water.

### Step-by-Step Solution:

1. **Understand the Concept of Salt Hydrolysis**:
- A salt formed from a weak acid and a strong base will produce a basic solution when dissolved in water. Conversely, a salt formed from a strong acid and a weak base will produce an acidic solution.

2. **Identify the Options**:
- Let's consider the possible compounds:
- A) Ammonium acetate (NH4C2H3O2)
- B) Ammonium chloride (NH4Cl)
- C) Ammonium sulfate ((NH4)2SO4)
- D) Sodium acetate (NaC2H3O2)

3. **Analyze Each Option**:
- **Option A: Ammonium acetate (NH4C2H3O2)**:
- Ammonium hydroxide (NH4OH) is a weak base and acetic acid (CH3COOH) is a weak acid. This salt will not produce a basic solution.
- **Option B: Ammonium chloride (NH4Cl)**:
- Ammonium hydroxide (NH4OH) is a weak base and hydrochloric acid (HCl) is a strong acid. This salt will produce an acidic solution.
- **Option C: Ammonium sulfate ((NH4)2SO4)**:
- Ammonium hydroxide (NH4OH) is a weak base and sulfuric acid (H2SO4) is a strong acid. This salt will also produce an acidic solution.
- **Option D: Sodium acetate (NaC2H3O2)**:
- Sodium hydroxide (NaOH) is a strong base and acetic acid (CH3COOH) is a weak acid. This salt will produce a basic solution.

4. **Conclusion**:
- Among the options analyzed, **Option D: Sodium acetate (NaC2H3O2)** is the compound whose 0.1 M solution is basic.

### Final Answer:
The compound whose 0.1 M solution is basic is **Sodium acetate (NaC2H3O2)**.